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cacovski's solution for 200: Consecutive Numbers, written in Java
public class ConsecutiveNumbers { public int longestSequence(int[] numbers) { int max=0; int count=1; for(int i=0; i<numbers.length-1; i++) { if(numbers[i]<numbers[i+1] && numbers[i+1]==0) { count++; } else { if(count>=max) { max=count; } count=1; } } return max; } public static void main(String[] CACE) { ConsecutiveNumbers con = new ConsecutiveNumbers(); int[] niza={1,2,3,4,2,3,0,2}; System.out.println(con.longestSequence(niza)); } }